The point (2,7) is successively reflected across the x-axis then the y-axis and then the x-axis again. What is the area of the rectangle formed by these two pointer
Accepted Solution
A:
Answer:The area of rectangle is [tex]56\ units^2[/tex]Step-by-step explanation:LetA(2,7)step 1The point A is reflected across the x-axiswe know thatThe rule of the reflection of a point across the x-axis is(x,y) -----> (x,-y)soA(2,7) ----->B(2,-7)step 2The point B is reflected across the y-axiswe know thatThe rule of the reflection of a point across the y-axis is(x,y) -----> (-x,y)B(2,-7) ----> C(-2,-7)step 3The point C is reflected across the x-axiswe know thatThe rule of the reflection of a point across the x-axis is(x,y) -----> (x,-y)soC(-2,-7) ----->D(-2,7) step 4Find the area of rectangle formed by A(2,7),B(2,-7),C(-2,-7),D(-2,7)using a graphing toolsee the attached figureThe area of rectangle is [tex]A=(4)(14)=56\ units^2[/tex]