HELPPPPPPP!!!!! Can someone help with this problem?? WILL MARK BRAINLIESTFind an equation for the line below.

Answer:[tex]y=\frac{-4}{3}x+\frac{-4}{3}[/tex] slope-intercept form[tex]y+4=\frac{-4}{3}(x-2)[/tex] point-slope formStep-by-step explanation:Equation of a line in point-slope form is y-y_1=m(x-x_1) where m is the slope and b is the [tex](x_1,y_1)[/tex] is a point on the line.So the m, slope, can be found by calculating the rise/run from one to another point on the line.So let's start at (2,-4) and count to (-4,4).So the rise is 8 and the run is -6.The slope is therefore 8/-6=-8/6=-4/3.Now if you didn't want to count because you can't count all the time.You could line up the two points and subtract vertically, then put 2nd difference over 1st difference. Like this:(  2  ,   -4)(-4  ,      4)---------------6          -8So the slope is -8/6=-4/3.Anyways now using any point on the line as [tex](x_1,y_1)[/tex] along with the slope we found we can finally put into our equation for point-slope form:[tex]y-y_1=m(x-x_1)[/tex]with [tex](x_1,y_1)=(2,-4)[/tex] and [tex]m=\frac{-4}{3}[/tex].This gives us:[tex]y-(-4)=\frac{-4}{3}(x-2)[/tex][tex]y+4=\frac{-4}{3}(x-2)[/tex]We probably want to put into y=mx+b form; not 100% sure so I will give you choices:y=mx+b is called slope-intercept form because it tells us the slope is m and the y-intercept is b.[tex]y+4=\frac{-4}{3}(x-2)[/tex]Distribute the -4/3 to the terms inside the ( ):[tex]y+4=\frac{-4}{3}x+\frac{8}{3}[/tex]Subtract 4 on both sides:[tex]y=\frac{-4}{3}x+\frac{8}{3}-4[/tex]Simplify the (8/3)-4:[tex]y=\frac{-4}{3}x+\frac{-4}{3}[/tex]